7(x)=31/2(x^2+1)-5

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Solution for 7(x)=31/2(x^2+1)-5 equation: 



7(x)=31/2(x^2+1)-5

We move all terms to the left:

7(x)-(31/2(x^2+1)-5)=0



Domain of the equation: 2(x^2+1)-5)!=0

x∈R



We multiply all the terms by the denominator


7x*2(x^2+1)-5)-(31=0

We add all the numbers together, and all the variables

7x*2(x^2+1)=0

Wy multiply elements

14x^2(x=0

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